A head to head comparison of the Iowa 2018 General Election gives us an idea of the break down of the voters.

Kim Reynolds received 667.3k (50.3 %) votes, beating Fred Hubbell who gained 631k (47.5 %) by 36.3k votes in Iowa.

Fred Hubbell won 11 counties out of the 99 counties that make up Iowa. The record shows that Kim Reynolds won 88 counties.

During the 2018 general elections, over 1M total number of votes were cast. Kim Reynolds got 667,275 (667k) over Fred Hubbell 630,986 (631k). He won the popular vote by 667,275 (667k). His victory in the State of Iowa (with 667,275 votes) represents 50.0% of his popular vote victory.

Top 15 Counties in General Elections

All Candidates (Gubernatorial General Elections)

These 15 counties play an important role in these Primary elections. If a candidate, can get a sizable majority in the largest counties (Polk, Polk and Polk), it becomes very difficult to win majorities in the smaller counties without voter outreach and increased voter participation in them.

Top 15 Counties Comparison in General Elections

General Elections
Kim Reynolds

General Elections
Fred Hubbell

Polk, Polk and Polk, three of the larger counties voted in favor of Fred Hubbell, giving him a 113k vote advantage.